Instead of trying to get yourself killed, first of all read the manual, maybe you dont know to operate the deck. Second if the deck still is giving trouble, start with connecting a dim bulb tester, best, in connection with a variac, if you have current to the fuses and they dont blow, there is failure farther inside the deck, and the dim bulb will show you if it is so, then check the schematics and start looking for failures, not working mechanics or electric components.

If you dont have any knowledge about electronics, leave it to a repair shop, BG are not that complicated and a good audio technician should be able to get it working.

Oops, double post.

I agree. 

It would be a bonus for us if you could post nice photos of the various parts of your Beogram!

There is a great fault-finding diagram in the service manual too.

Ok thanks guys,

I will look through the diagram and start trouble shooting. I will get a dim bulb tested and see what that shows.

As far as the pictures I could probably post some on the weekend for you to look over.

Thanks again guys, I will keep you updated.

Hi,

Any new developments then?

Where in Australia are you Beowaff? 

Hey guys,

No new developments at the moment, I have been busy with work so I haven't had the time to look into it further! 

Andrew im in Melbourne.

I will keep you all updated.

I am based in Melbourne and know someone who can work on these units who knows his way around them pretty well, if you want his details shoot me a message.

Andrew

I just wanted to know if anyone knows someone in Melbourne who can look at an fix my Beogram? Any help would be really appreciated.

Thanks

Dillen wrote:

If you live in a 110-120V area and moved the Beogram from a 220-240V area, you will have to set the mains voltage
on the switch (unpowered) and change the fuse accordingly.
If 250mA was correct for use in 110-120V areas, you will need 500mA to stop the fuse(s) from blowing in 220-240V areas.

Remember Ohms law ? 🤒

Martin

If a device consumes the same amount of power, then according to Ohm, the current will be reduced be a half, when the voltage doubles.

Roughly (as with AC current it's different)   P= U x I